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BaseCTF week3 (web&misc 部分)wp

2024-10-05 19:00:05Python资料围观30

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BaseCTF week3

杂项

[Week3] 白丝上的flag

描述:某出题人赠送大家flag时遭遇了信号干扰, 幸好我们在不知名小网站找到了写入flag前的图片, 尝试还原信息吧!

提示:flag是单色

附件:

#task.py
from PIL import Image
from random import randint
import sys

def ez_add(a,b,c,d):
    global iv
    h = (a+b+c+d+iv) % 256
    e = b
    f = c
    g = d
    iv = (b+c+d+iv) % 256
    return e,f,g,h

def confuse(data):
    r,g,b,a = data
    for _ in range(8):
        r,g,b,a = ez_add(r,g,b,a)
    return r,g,b,a

def confuse_image(flag):
    global iv
    iv = flag.getpixel((1,1))[0]
    img = Image.new('RGBA', (flag.width, flag.height))
    for w in range(img.width):
        for h in range(img.height):
            img.putpixel((w, h), confuse(flag.getpixel((w,h))))
    return img

if __name__ == '__main__':
    iv = 0
    flag = Image.open("./de_image.png")
    img = confuse_image(flag)
    img.save("en_image.png")

解密思路:

  1. 逆向 confuse 函数: 由于 confuse 函数是对像素进行简单的加法运算,我们可以通过逆向运算来解密。
  2. 单色图像特点: 单色图像的每个像素的 RGB 值都相同,我们可以利用这个特点来简化解密过程。

脚本:

from PIL import Image

def ez_sub(h, e, f, g):
    global iv
    a = (h - e - f - g - iv) % 256
    iv = (e + f + g + iv) % 256
    return a

def unconfuse(data):
    r, g, b, a = data
    for _ in range(8):
        r = ez_sub(r, g, b, a)
    return r, g, b, a

def unconfuse_image(img):
    global iv
    iv = img.getpixel((1, 1))[0]
    flag = Image.new('RGBA', (img.width, img.height))
    for w in range(img.width):
        for h in range(img.height):
            flag.putpixel((w, h), unconfuse(img.getpixel((w, h))))
    return flag

if __name__ == '__main__':
    iv = 0
    img = Image.open("en_image.png")
    flag = unconfuse_image(img)
    flag.save("de_image_decrypted.png")

得到de_image_decrypted.png,使用Stegsolve.jar查看red plane 0发现flag

BaseCTF{there_1s_the_flag@}


[Week3] 纯鹿人

附件:

cGFzc3dvcmTvvJppa3VuaWt1bg==

base64解码
password:ikunikun

这里我一开始的思路就是将文档中的表情包保存下来使用WinHex打开,并没用什么发现,然后搜索发现可能是使用jphs,但是最后发现不行

没用思路就暂时放弃了

后面就是在群里看见有人讨论上周[Week2]哇!珍德食泥鸭的另一种解法

于是我试着将文档改为zip后缀,发现

将其丢尽WinHex编辑器中得到

使用foremost进行分离得到一个新的zip文件,密码为ikunikun,即可得到flag

CTF-MISC隐写总结_ctf mp4隐写-CSDN博客



[Week3] 我要吃火腿!

附件:

#我要吃火腿!.txt

~呜嗷嗷嗷嗷呜啊嗷呜~呜嗷呜呜~嗷~嗷啊嗷啊呜嗷嗷嗷呜~嗷~呜嗷嗷~~嗷嗷嗷呜啊呜啊~呜嗷呜呜~嗷呜啊啊嗷啊呜嗷呜~呜~嗷~呜嗷~~啊嗷嗷嗷呜啊呜啊啊呜嗷呜呜~嗷嗷嗷啊嗷啊呜嗷呜~~~嗷~呜呜嗷呜~嗷嗷嗷呜呜~嗷啊呜嗷呜呜~嗷~~啊嗷啊呜嗷嗷~嗷~嗷~呜呜嗷~嗷嗷嗷嗷呜呜嗷啊~呜嗷呜呜~嗷嗷嗷啊嗷啊呜嗷嗷啊呜~嗷~呜呜呜~~嗷嗷嗷呜啊呜啊嗷呜嗷呜呜~呜啊~啊嗷啊呜~~啊啊~嗷~呜呜嗷呜呜嗷嗷嗷呜啊嗷~嗷呜嗷呜呜~嗷嗷~啊嗷啊呜嗷嗷嗷嗷~嗷~呜嗷嗷啊~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜~嗷呜啊啊嗷啊呜嗷呜嗷嗷~嗷~呜呜呜嗷~嗷嗷嗷呜啊呜嗷~呜嗷呜呜~呜~嗷啊嗷啊呜嗷呜~~~嗷~呜嗷~~啊嗷嗷嗷呜啊嗷啊呜呜嗷呜呜~嗷嗷嗷啊嗷啊呜嗷嗷呜~~嗷~呜呜嗷呜嗷嗷嗷嗷呜呜嗷~嗷呜嗷呜呜啊呜嗷呜啊嗷啊呜啊啊呜呜~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜呜嗷呜~嗷嗷嗷呜啊嗷呜嗷呜嗷呜呜~嗷呜嗷啊嗷啊呜~~啊啊~嗷~呜呜嗷嗷呜嗷嗷嗷呜啊呜~嗷呜嗷呜呜~呜啊~啊嗷啊呜嗷嗷嗷嗷~嗷~呜呜呜嗷啊嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊呜呜嗷啊嗷啊呜~嗷啊~~嗷~呜嗷~啊啊嗷嗷嗷呜呜呜嗷~呜嗷呜呜~呜~~啊嗷啊呜~呜~~~嗷~呜嗷呜呜~嗷嗷嗷呜呜嗷~~呜嗷呜呜啊嗷呜~啊嗷啊呜~呜啊~~嗷~呜呜呜呜~嗷嗷嗷呜呜呜啊呜呜嗷呜呜啊呜啊嗷啊嗷啊呜~嗷呜~~嗷~呜嗷嗷~~嗷嗷嗷呜呜呜嗷~呜嗷呜呜~呜~~啊嗷啊呜~呜嗷呜~嗷~呜嗷啊嗷~嗷嗷嗷呜呜~嗷嗷呜嗷呜呜呜啊嗷呜啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷呜~啊嗷啊呜啊啊呜呜~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜呜呜呜啊嗷嗷嗷呜啊嗷~嗷呜嗷呜呜~呜啊~啊嗷啊呜嗷嗷嗷~~嗷~呜嗷嗷~~嗷嗷嗷呜啊嗷嗷啊呜嗷呜呜~呜呜~啊嗷啊呜嗷嗷嗷嗷~嗷~呜呜嗷~呜嗷嗷嗷呜呜嗷啊~呜嗷呜呜~嗷嗷嗷啊嗷啊呜嗷嗷啊呜~嗷~呜呜呜~~嗷嗷嗷呜啊呜啊嗷呜嗷呜呜~呜啊~啊嗷啊呜~~啊啊~嗷~呜呜嗷呜呜嗷嗷嗷呜啊嗷~嗷呜嗷呜呜~嗷嗷~啊嗷啊呜嗷嗷嗷嗷~嗷~呜嗷嗷啊~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷~啊啊嗷啊呜嗷呜~呜~嗷~呜呜嗷嗷呜嗷嗷嗷呜呜嗷啊啊呜嗷呜呜啊嗷嗷嗷啊嗷啊呜~嗷啊~~嗷~呜呜嗷嗷嗷嗷嗷嗷呜啊呜呜啊呜嗷呜呜啊嗷呜~啊嗷啊呜嗷嗷嗷呜~嗷~呜嗷呜啊呜嗷嗷嗷呜嗷啊~呜呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜~嗷啊~啊嗷啊呜嗷嗷~嗷~嗷~呜呜呜嗷~嗷嗷嗷呜啊嗷呜嗷呜嗷呜呜啊嗷呜~啊嗷啊呜~呜啊嗷~嗷~呜嗷嗷~~嗷嗷嗷呜啊嗷呜呜呜嗷呜呜~呜嗷嗷啊嗷啊呜嗷呜~~~嗷~呜呜嗷呜嗷嗷嗷嗷呜啊嗷呜嗷呜嗷呜呜~呜啊呜啊嗷啊呜嗷呜~呜~嗷~呜呜嗷嗷嗷嗷嗷嗷呜啊呜~嗷呜嗷呜呜啊嗷~~啊嗷啊呜嗷嗷嗷呜~嗷~呜嗷嗷~呜嗷嗷嗷呜啊呜呜呜呜嗷呜呜~嗷~嗷啊嗷啊呜嗷嗷~嗷~嗷~呜呜嗷嗷~嗷嗷嗷呜呜嗷啊~呜嗷呜呜啊嗷嗷嗷啊嗷啊呜~嗷呜嗷~嗷~呜~啊啊呜嗷嗷嗷呜嗷啊~呜呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜~嗷~呜啊嗷啊呜嗷嗷啊啊~嗷~呜呜呜嗷呜嗷嗷嗷呜呜嗷嗷~呜嗷呜呜~嗷嗷嗷啊嗷啊呜~嗷啊~~嗷~呜呜嗷啊嗷嗷嗷嗷呜啊嗷嗷呜呜嗷呜呜啊嗷呜~啊嗷啊呜嗷呜~呜~嗷~呜呜嗷嗷嗷嗷嗷嗷呜啊嗷嗷呜呜嗷呜呜~嗷~啊啊嗷啊呜嗷嗷嗷嗷~嗷~呜嗷嗷呜~嗷嗷嗷呜啊嗷~~呜嗷呜呜~嗷~嗷啊嗷啊呜嗷嗷啊呜~嗷~呜嗷嗷呜~嗷嗷嗷呜啊嗷呜~呜嗷呜呜~嗷啊嗷啊嗷啊呜嗷呜~~~嗷~呜呜嗷嗷嗷嗷嗷嗷呜呜嗷~嗷呜嗷呜呜啊嗷嗷嗷啊嗷啊呜~呜呜呜~嗷~呜~啊啊呜嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜啊嗷呜~呜嗷呜呜~嗷啊嗷啊嗷啊呜嗷呜~~~嗷~呜呜嗷嗷嗷嗷嗷嗷呜呜~~啊呜嗷呜呜~嗷嗷嗷啊嗷啊呜~~啊嗷~嗷~呜嗷嗷~~嗷嗷嗷呜呜~嗷呜呜嗷呜呜啊呜呜嗷啊嗷啊呜~嗷啊~~嗷~呜呜嗷呜~嗷嗷嗷呜啊嗷呜嗷呜嗷呜呜~嗷呜嗷啊嗷啊呜~~啊啊~嗷~呜呜嗷嗷呜嗷嗷嗷呜啊呜~嗷呜嗷呜呜~呜啊~啊嗷啊呜嗷嗷嗷嗷~嗷~呜呜呜嗷啊嗷嗷嗷呜呜~~啊呜嗷呜呜~嗷嗷嗷啊嗷啊呜~嗷啊~~嗷~呜嗷嗷呜嗷嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊呜啊啊啊嗷啊呜~~啊嗷~嗷~呜~啊啊呜嗷嗷嗷呜嗷啊~呜呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜~呜~啊啊嗷啊呜嗷嗷呜嗷~嗷~呜呜呜嗷~嗷嗷嗷呜啊嗷啊~呜嗷呜呜啊嗷呜~啊嗷啊呜嗷嗷啊啊~嗷~呜呜呜~~嗷嗷嗷呜啊嗷啊嗷呜嗷呜呜~嗷呜呜啊嗷啊呜~嗷嗷~~嗷~呜呜嗷~啊嗷嗷嗷呜啊呜啊嗷呜嗷呜呜~呜啊~啊嗷啊呜嗷呜啊~~嗷~呜呜呜呜嗷嗷嗷嗷呜啊呜呜~呜嗷呜呜啊~呜啊啊嗷啊呜嗷嗷嗷呜~嗷~呜呜嗷啊嗷嗷嗷嗷呜啊嗷~~呜嗷呜呜~嗷~嗷啊嗷啊呜~嗷呜~~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷啊啊呜嗷呜呜~呜~啊啊嗷啊呜嗷嗷~呜~嗷~呜嗷嗷呜啊嗷嗷嗷呜呜嗷~嗷呜嗷呜呜啊嗷呜~啊嗷啊呜嗷嗷~嗷~嗷~呜呜呜嗷啊嗷嗷嗷呜呜嗷嗷~呜嗷呜呜~嗷~呜啊嗷啊呜~呜呜呜~嗷~呜~啊啊呜嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜呜嗷嗷~呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷啊~~嗷~呜嗷嗷~~嗷嗷嗷呜啊嗷啊呜呜嗷呜呜啊嗷呜呜啊嗷啊呜嗷呜嗷啊~嗷~呜呜呜嗷呜嗷嗷嗷呜啊嗷~嗷呜嗷呜呜~呜啊~啊嗷啊呜嗷嗷嗷嗷~嗷~呜嗷嗷呜~嗷嗷嗷呜啊嗷呜~呜嗷呜呜~嗷啊嗷啊嗷啊呜嗷呜~~~嗷~呜呜嗷嗷嗷嗷嗷嗷呜呜嗷~嗷呜嗷呜呜呜啊嗷呜啊嗷啊呜啊啊呜呜~嗷~呜呜呜呜~嗷嗷嗷呜啊嗷嗷啊呜嗷呜呜~呜啊呜啊嗷啊呜~~啊啊~嗷~呜呜呜呜啊嗷嗷嗷呜啊嗷~嗷呜嗷呜呜~呜啊~啊嗷啊呜嗷嗷嗷~~嗷~呜嗷~~啊嗷嗷嗷呜啊嗷啊~呜嗷呜呜~嗷啊嗷啊嗷啊呜嗷嗷啊嗷~嗷~呜嗷嗷呜~嗷嗷嗷呜呜嗷啊啊呜嗷呜呜啊啊~~啊嗷啊呜嗷嗷~嗷~嗷~呜呜嗷~嗷嗷嗷嗷呜啊嗷嗷啊呜嗷呜呜~呜啊呜啊嗷啊呜嗷嗷呜~~嗷~呜嗷嗷~呜嗷嗷嗷呜啊嗷~呜呜嗷呜呜~呜呜~啊嗷啊呜嗷嗷嗷啊~嗷~呜嗷嗷呜啊嗷嗷嗷呜呜嗷~~呜嗷呜呜啊嗷呜~啊嗷啊呜~嗷嗷啊~嗷~呜嗷啊呜~嗷嗷嗷呜啊嗷呜嗷呜嗷呜呜~嗷呜嗷啊嗷啊呜~嗷啊呜~嗷~呜呜嗷啊呜嗷嗷嗷呜啊呜嗷~呜嗷呜呜~嗷~啊啊嗷啊呜~嗷嗷啊~嗷~呜嗷嗷啊嗷啊

解码网站:兽音译者在线编码解码 - 兽音翻译咆哮体加密解密 (iiilab.com)

def xor_with_ham(input_file, output_file):
    ham_bytes = [0x48, 0x61, 0x6D]
    
    with open(input_file, 'rb') as f:
        data = bytearray(f.read())

    for i in range(len(data)):
        data[i] ^= ham_bytes[i % 3]

    with open(output_file, 'wb') as f:
        f.write(data)

xor_with_ham('Hamorl.jpg', 'Ham.jpg')

解密脚本

def xor_with_ham_decrypt(input_file, output_file):
    ham_bytes = [0x48, 0x61, 0x6D]

    with open(input_file, 'rb') as f:
        data = bytearray(f.read())

    for i in range(len(data)):
        data[i] ^= ham_bytes[i % 3]

    with open(output_file, 'wb') as f:
        f.write(data)


# 使用函数解密
xor_with_ham_decrypt('Ham.jpg', 'Hamorl.jpg')

得到Hamorl.jpg

不过还是损坏的,修改文件头为ffd8ffe1保存即可

到这里就不会了,试了很大种方法

看了官方wp,真的绷不住了

之前用binwalk看了一下以为没啥,结果foremost有了(可恶

SSTV

MMSSTV & RX-SSTV 两款图像解码软件 安装文件下载 - 悟透 - 博客园 (cnblogs.com)

Virtual Audio Cable - Downloads (muzychenko.net)

[三、音频隐写Audacity、deepsound、dtmf2num、MMSSTV、虚拟声卡、MP3Stego]-CSDN博客



[Week3] Base revenge

描述:Not just Base
附件:

VGl0bGU6IFRoZSBFbmlnbWF0aWMgQ29kZSBvZiBNaXNjIEJhc2U2NE==
R3JlZXRpbmdzLCBwdXp6bGUgZW50aHVzaWFzdHMgYW5kIGNvZGVicmVha2VycyBhbGlrZSEgVG9kYXks
d2UgZGVsdmUgaW50byB0aGUgcmVhbG0gb2YgdGhlIGVuaWdtYXRpYyBNaXNjIEJhc2U2NCy=
YSBjcnlwdG9ncmFwaGljIHB1enpsZSB0aGF0IGNoYWxsZW5nZXMgdGhlIGtlZW5lc3QgbWluZHMu
QXJlIHlvdSByZWFkeSB0byBlbWJhcmsgb24gYSBqb3VybmV5IG9mIGRlY29kaW5nIGFuZCBkaXNjb3Zlcnk/
SW1hZ2luZSB5b3Vyc2VsZiBpbiB0aGUgbWlkc3Qgb2YgYSBkaWdpdGFsIGxhYnlyaW50aCy=
d2hlcmUgc3RyaW5ncyBvZiBjaGFyYWN0ZXJzIGhvbGQgc2VjcmV0cyB3YWl0aW5nIHRvIGJlIHVudmVpbGVkLm==
TWlzYyBCYXNlNjQgaXMgbm90IHlvdXIgb3JkaW5hcnkgY2lwaGVy4oCUaXQgY29uY2VhbHMgbWVzc2FnZXP=
aW4gcGxhaW4gc2lnaHQsIGF3YWl0aW5nIHRob3NlIHdpdGggdGhlIHJpZ2h0IHRvb2xz
YW5kIHNraWxscyB0byBkZWNpcGhlciBpdHMgY29kZS6=
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give you a hint:{Gs1h_1h_nb_srmg}

对提示进行分析:

{Gs1h_1h_nb_srmg}

atbash在线解密:
{th1s_1s_my_hint}

上述base64解密发现没有什么有用的信息,提取出首写字母也没用

wp:base64隐写,第一次听说这个东西

使用b64steg隐写工具提取出来

Nicolas-yuan/b64steganography: b64隐写提取工具 (github.com)

脚本:

'''
Author: 拾柒
Date: 2020-11-12 21:17:24
LastEditTime: 2020-11-14 18:29:23
Description: Base64 steganography
'''
'''
隐写原理:
base64将二进制以6bit为一个字符编码进行重新编码,如果二进制长度为6的倍数,则编码无冗余,
若长度不是6的倍数,则存在2bit(或4bit)长度的二进制无法编码,此时需要填充长度为4bit(或2bit)的0完成编码,
而后填充长度为12bit(或6bit)的0表示前面的数据填充了几个0,用于解码,最后填充的0编码为‘=’,
此时可把长度为4bit(或2bit)的填充数据0替换为要隐写的数据二进制值,然后再编码完成隐写.
'''
'''
提取原理1:
base64根据等号数量判断隐写bit长度,读取等号前一个字符的base64编码,提取尾部对应长度的bit,组合后解码.
提取原理2:
base64隐写的数据对解密无影响,但隐写后加密的字符与未隐写加密的字符不一样,
差值(不能用ASCII码的差值,要用base64编码的差值)是隐写的二进制对应的十进制值.
使用方法:
cmd中输入“ python b64stegano.py [filename] [a,b]”
'''
import sys
import base64

def to_bin(value, num):#十进制数据,二进制位宽
	bin_chars = ""
	temp = value
	for i in range(num):
		bin_char = bin(temp % 2)[-1]
		temp = temp // 2
		bin_chars = bin_char + bin_chars
	return bin_chars.upper()#输出指定位宽的二进制字符串

base64_dica={
    'A':'000000','B':'000001','C':'000010','D':'000011','E':'000100','F':'000101','G':'000110','H':'000111',
    'I':'001000','J':'001001','K':'001010','L':'001011','M':'001100','N':'001101','O':'001110','P':'001111',
    'Q':'010000','R':'010001','S':'010010','T':'010011','U':'010100','V':'010101','W':'010110','X':'010111',
    'Y':'011000','Z':'011001','a':'011010','b':'011011','c':'011100','d':'011101','e':'011110','f':'011111',
    'g':'100000','h':'100001','i':'100010','j':'100011','k':'100100','l':'100101','m':'100110','n':'100111',
    'o':'101000','p':'101001','q':'101010','r':'101011','s':'101100','t':'101101','u':'101110','v':'101111',
    'w':'110000','x':'110001','y':'110010','z':'110011','0':'110100','1':'110101','2':'110110','3':'110111',
    '4':'111000','5':'111001','6':'111010','7':'111011','8':'111100','9':'111101','+':'111110','/':'111111'
}#base64编码对应表,用于提取原理1

base64_dicb={
    'A':0,'B':1,'C':2,'D':3,'E':4,'F':5,'G':6,'H':7,
    'I':8,'J':9,'K':10,'L':11,'M':12,'N':13,'O':14,'P':15,
    'Q':16,'R':17,'S':18,'T':19,'U':20,'V':21,'W':22,'X':23,
    'Y':24,'Z':25,'a':26,'b':27,'c':28,'d':29,'e':30,'f':31,
    'g':32,'h':33,'i':34,'j':35,'k':36,'l':37,'m':38,'n':39,
    'o':40,'p':41,'q':42,'r':43,'s':44,'t':45,'u':46,'v':47,
    'w':48,'x':49,'y':50,'z':51,'0':52,'1':53,'2':54,'3':55,
    '4':56,'5':57,'6':58,'7':59,'8':60,'9':61,'+':62,'/':63
}#base64编码对应表,用于提取原理2

hidebit = ''#存储隐写的bit数据
m = ''#存储结果
argvs = sys.argv#获取命令行参数
fc = open(argvs[1],'r')#打开文件
lines = fc.read().split('\n')#读取内容,并按行分割

##################提取原理1
if argvs[2] == 'a':
#判断每行是否有隐写数据,有读取存入hidebit
    for line in lines:
        if line != '':
            if line[-1] == '=':#判断最后一个字符是不是‘=’,
                if line[-2] == '=':#判断倒数第二个字符是不是‘=’              
                        hidebit += base64_dica[line[-3]][2:]                  
                else:
                        hidebit += base64_dica[line[-2]][4:]
            else:
                pass
###################提取原理2
elif argvs[2] == 'b':
    #判断每行是否有隐写数据,有计算差值后转为二进制存入hidebit
    for line in lines:
        line_row = base64.b64encode(base64.b64decode(line)).decode('utf-8')
        if line != '':
            if line[-1] == '=':#判断最后一个字符是不是‘=’,
                if line[-2] == '=':#判断倒数第二个字符是不是‘=’
                    temp = to_bin(base64_dicb[line[-3]]-base64_dicb[line_row[-3]],4)
                    hidebit += temp
                else:
                    temp = to_bin(base64_dicb[line[-2]]-base64_dicb[line_row[-2]],2)
                    hidebit += temp
            else:
                pass
#将二进制转化十进制,即ASCII码,再转化为字符
for i in range(0,len(hidebit),8):
    m += chr(int(hidebit[i:i+8],2))
print(m)

使用 python b64stegano.py stego.txt a 或 python b64stegano.py stego.txt b
即可得到隐写信息

JnUaAFMFImgANSEuAWYuBE9SyaYpC2ldBrU9

结合提示,使用atbash解码

这里在线网站解码出来的都是小写,所以写了个脚本

from string import ascii_lowercase, ascii_uppercase

def atbashAttack(plaintext: str):
    dir_atbash_lower = ascii_lowercase[::-1]
    dir_atbash_upper = ascii_uppercase[::-1]
    res = ''
    for s in plaintext:
        if s.isupper():
            res += dir_atbash_upper[ascii_uppercase.index(s)]
        elif s.islower():
            res += dir_atbash_lower[ascii_lowercase.index(s)]
        else:
            res += s
    return res

plaintext = 'JnUaAFMFImgANSEuAWYuBE9SyaYpC2ldBrU9'
ciphertext = atbashAttack(plaintext)
print("Atbash解密结果:", ciphertext)

得到:

QmFzZUNURntZMHVfZDBfYV9HbzBkX2owYiF9

base64解码得到

BaseCTF{Y0u_d0_a_Go0d_j0b!}


[Week3] 这是一个压缩包

描述:不要只会用工具噢

附件:这是一个压缩包.zip

需要密码,WinHex打开发现

QmFzZUNURj8/Pz8/P0ZUQ2VzYUI=

base64解密:
BaseCTF??????FTCesaB

官方解:

中间缺少6位?,样式是对称的

利用python中zipfile,简单写个脚本爆破一下即可

hashcat也能解决

[https://hashcat.net/files/hashcat-5.1.0.7z]

import zipfile
zfile=zipfile.ZipFile("1.zip",'r')

for i in range(33,128):
    for j in range(33,128):
        for k in range(33,128):
            mask="BaseCTF"+chr(i)+chr(j)+chr(k)+chr(k)+chr(j)+chr(i)+"FTCesaB"
            try:
                zfile.extractall(pwd=mask.encode('utf-8'))
                print(mask)
                exit()
            except:
                pass
#BaseCTF_h11h_FTCesaB


[Week3] broken.mp4

描述:

破防时刻:录屏录到一半,断电关机了。签个到吧

BaseCTF Week2 讲解视频 (broken).mp4

附件:

不是,这真是一个签到题啊

光顾着做题确实没看第一个mp4的内容,确实想到了mp4文件会损坏,但是刚接触misc有很多东西确实没见过,又学到了

视频中的原文章

【视频图像篇】MP4受损视频修复方法(一)_untrunc-CSDN博客

github.com

得到录制2.mp4_fixed.mp4,打开得到flag



[Week3] 外星信号

描述:

在一次秘密任务中截获到了一段对话,地球人向地外发送了一段秘语,外星返回了一段外星信号,赶快来破译密码吧(flag小写)

提示:

嘶…音频播放时长和总时长不不对劲啊

附件:外星信号.mp3

摩尔斯电码音频解码器 – Morse Code Magic

得到:

THERE-IS-NO-FLAG-HERE-THERE-IS-NO-FLAG-HERE-THERE-IS-NO-FLAG-HERE-LET-US-GOBASECTF#2EBE6FDC-60DC-

得到flag的前半部分

BASECTF#2EBE6FDC-60DC-

foremost一下得到一个zip,解压得到flag.mp3

使用mmsstv即可得到flag

这里我用的是mmsstv是斜的,看群里说rx-sstv是正的,这里我就不用浪费时间了

发现含有摩斯密码,抄下来解码就行了

....-/----./.-/....-/-....-/.-/
----./----./..---/-....-/...-
-/-.../-.../-../...../-..../..-./
...--/..-./-../-----/-.../---
-.-

得到

49A4-A992-3BBD56F3FD0B%u3d

转为小写得到

BaseCTF{2ebe6fdc-60dc-49a4-a992-3bbd56f3fd0b}



web

[Week3] 滤个不停

描述:过滤这么多还怎么玩!等等…不对劲

靶机:

 <?php
highlight_file(__FILE__);
error_reporting(0);

$incompetent = $_POST['incompetent'];
$Datch = $_POST['Datch'];

if ($incompetent !== 'HelloWorld') {
    die('写出程序员的第一行问候吧!');
}

//这是个什么东东???
$required_chars = ['s', 'e', 'v', 'a', 'n', 'x', 'r', 'o'];
$is_valid = true;

foreach ($required_chars as $char) {
    if (strpos($Datch, $char) === false) {
        $is_valid = false;
        break;
    }
}

if ($is_valid) {

    $invalid_patterns = ['php://', 'http://', 'https://', 'ftp://', 'file://' , 'data://', 'gopher://'];

    foreach ($invalid_patterns as $pattern) {
        if (stripos($Datch, $pattern) !== false) {
            die('此路不通换条路试试?');
        }
    }


    include($Datch);
} else {
    die('文件名不合规 请重试');
}
?>
写出程序员的第一行问候吧!

第一个if是基操

$incompetent = $_POST['incompetent'];

if ($incompetent !== 'HelloWorld') {
    die('写出程序员的第一行问候吧!');
}

绕过:

incompetent=HelloWorld

第二个if语句要求Datch里面含有那些字符,

$Datch = $_POST['Datch'];

//这是个什么东东???
$required_chars = ['s', 'e', 'v', 'a', 'n', 'x', 'r', 'o'];
$is_valid = true;

foreach ($required_chars as $char) {
    if (strpos($Datch, $char) === false) {
        $is_valid = false;
        break;
    }
} 

strpos可以使用数组形式绕过

Datch[]=xxx

参考:

Bugku——strpos数组绕过_strpos绕过-CSDN博客

也可以使用%0a绕过,虽然这里用不到

这里由于$Datch涉及到了两个if语句

不能绕过,因为此时使用这个方法绕过时$Datch 是一个数组,而 strposstripos 函数期望的是字符串参数。会出现警告信息。(调试)

第三个if语句

if ($is_valid) {

    $invalid_patterns = ['php://', 'http://', 'https://', 'ftp://', 'file://' , 'data://', 'gopher://'];

    foreach ($invalid_patterns as $pattern) {
        if (stripos($Datch, $pattern) !== false) {
            die('此路不通换条路试试?');
        }
    }


    include($Datch);
} else {
    die('文件名不合规 请重试');
} 

注意这里是stripos

tips:

strpos系列函数
函数描述版本
strpos查找字符串首次出现的位置PHP 4, PHP 5, PHP 7
stripos查找字符串首次出现的位置(不区分大小写)PHP 5, PHP 7
strrpos计算指定字符串在目标字符串中最后一次出现的位置PHP 4, PHP 5, PHP 7
strripos计算指定字符串在目标字符串中最后一次出现的位置(不区分大小写)PHP 5, PHP 7
mb_strpos查找字符串在另一个字符串中首次出现的位置PHP 4 >= 4.0.6, PHP 5, PHP 7
strstr查找字符串的首次出现PHP 4, PHP 5, PHP 7
stristrstrstr() 函数的忽略大小写版本PHP 4, PHP 5, PHP 7
substr_count计算字串出现的次数PHP 4, PHP 5, PHP 7

mb* 相关的函数也可, 比如说mb_strpos是基于字符数执行一个多字节安全的 strpos() 操作。

到这里我发现行不通,于是回到第二个if条件,想着把把它们组成弄成一个不存在的后缀,然后解析时好像就会忽略这个后缀,但是下一个疑点又出来了,我不知目标网站中存在哪些文件

接着上网搜了一下nginx,发现

Nginx中的日志分两种,一种是error.log,一种是access.log。error.log可以配置成任意级别,默认级别是error,用来记录Nginx运行期间的处理流程相关的信息;access.log指的是访问日志,用来记录服务器的接入信息(包括记录用户的IP、请求处理时间、浏览器信息等)。

更好包含可以使用的字符,搜嘎

抓包传参,在ua中进行RCE,这里要发两次包
(我们写入的php代码会被解析从而进行RCE)

查看flag,这里我查看不了flag,重新开一下容器就解决了(同样发两次)

BaseCTF{2b693b60-a49b-4bf6-9798-565d0ef323f7}

参考:

ctfshow-web4(Nginx访问日志写shell) - 你呀你~ - 博客园 (cnblogs.com)

ctfshow-web4(文件包含&日志注入)_ctfshow web4-CSDN博客



[Week3] 玩原神玩的

描述:flag怎么被分解成$array了,不管了,原神,启动!

靶机:

 <?php
highlight_file(__FILE__);
error_reporting(0);

include 'flag.php';
if (sizeof($_POST['len']) == sizeof($array)) {
  ys_open($_GET['tip']);
} else {
  die("错了!就你还想玩原神?❌❌❌");
}

function ys_open($tip) {
  if ($tip != "我要玩原神") {
    die("我不管,我要玩原神!😭😭😭");
  }
  dumpFlag();
}

function dumpFlag() {
  if (!isset($_POST['m']) || sizeof($_POST['m']) != 2) {
    die("可恶的QQ人!😡😡😡");
  }
  $a = $_POST['m'][0];
  $b = $_POST['m'][1];
  if(empty($a) || empty($b) || $a != "100%" || $b != "love100%" . md5($a)) {
    die("某站崩了?肯定是某忽悠干的!😡😡😡");
  }
  include 'flag.php';
  $flag[] = array();
  for ($ii = 0;$ii < sizeof($array);$ii++) {
    $flag[$ii] = md5(ord($array[$ii]) ^ $ii);
  }
  
  echo json_encode($flag);
} 错了!就你还想玩原神?❌❌❌

针对第一个flag,我们应该爆破出len的程度,一个一个试发现为45

len[]=0&len[]=1&len[]=2&len[]=3&len[]=4&len[]=5&len[]=6&len[]=7&len[]=8&len[]=9&len[]=10&len[]=11&len[]=12&len[]=13&len[]=14&len[]=15&len[]=16&len[]=17&len[]=18&len[]=19&len[]=20&len[]=21&len[]=22&len[]=23&len[]=24&len[]=25&len[]=26&len[]=27&len[]=28&len[]=29&len[]=30&len[]=31&len[]=32&len[]=33&len[]=34&len[]=35&len[]=36&len[]=37&len[]=38&len[]=39&len[]=40&len[]=41&len[]=42&len[]=43&len[]=44

使用hackerbar进行传参,因为BP里面输入不了中文

绕过最后两个if语句

发现只绕过了一个if语句,原来% 是一个特殊字符,因为它用于表示百分号编码(也称为URL编码)。如果你要在URL中直接包含 %,你需要对其进行编码。% 的URL编码是 %25

成功绕过,回显得到

["3295c76acbf4caaed33c36b1b5fc2cb1","26657d5ff9020d2abefe558796b99584","73278a4a86960eeb576a8fd4c9ec6997","ec8956637a99787bd197eacd77acce5e","e2c420d928d4bf8ce0ff2ec19b371514","43ec517d68b6edd3015b3edc9a11367b","ea5d2f1c4608232e07d3aa3d998e5135","c8ffe9a587b126f152ed3d89a146b445","f457c545a9ded88f18ecee47145a72c0","03afdbd66e7929b125f8597834fa83a4","093f65e080a295f8076b1c5722a46aa2","03afdbd66e7929b125f8597834fa83a4","698d51a19d8a121ce581499d7b701668","d82c8d1619ad8176d665453cfb2e55f0","b53b3a3d6ab90ce0268229151c9bde11","9f61408e3afb633e50cdf1b20de6f466","7f39f8317fbdb1988ef4c628eba02591","07e1cd7dca89a1678042477183b7ac3f","a1d0c6e83f027327d8461063f4ac58a6","7f6ffaa6bb0b408017b62254211691b5","d67d8ab4f4c10bf22aa353e27879133c","9f61408e3afb633e50cdf1b20de6f466","e369853df766fa44e1ed0ff613f563bd","5fd0b37cd7dbbb00f97ba6ce92bf5add","67c6a1e7ce56d3d6fa748ab6d9af3fd7","3416a75f4cea9109507cacd8e2f2aefc","b53b3a3d6ab90ce0268229151c9bde11","1c383cd30b7c298ab50293adfecb7b18","3416a75f4cea9109507cacd8e2f2aefc","da4fb5c6e93e74d3df8527599fa62642","c8ffe9a587b126f152ed3d89a146b445","c0c7c76d30bd3dcaefc96f40275bdc0a","735b90b4568125ed6c3f678819b6e058","14bfa6bb14875e45bba028a21ed38046","fc490ca45c00b1249bbe3554a4fdf6fb","37693cfc748049e45d87b8c7d8b9aacd","37693cfc748049e45d87b8c7d8b9aacd","98f13708210194c475687be6106a3b84","3c59dc048e8850243be8079a5c74d079","fc490ca45c00b1249bbe3554a4fdf6fb","33e75ff09dd601bbe69f351039152189","4e732ced3463d06de0ca9a15b6153677","33e75ff09dd601bbe69f351039152189","c16a5320fa475530d9583c34fd356ef5","43ec517d68b6edd3015b3edc9a11367b"]

气死了气死了,这里一开始使用了python编写脚本,死活不对

发现

然后我就去试了试php,就可以了

脚本:

<?php

$md5 = [
    "3295c76acbf4caaed33c36b1b5fc2cb1", "26657d5ff9020d2abefe558796b99584",
    "73278a4a86960eeb576a8fd4c9ec6997", "ec8956637a99787bd197eacd77acce5e",
    "e2c420d928d4bf8ce0ff2ec19b371514", "43ec517d68b6edd3015b3edc9a11367b",
    "ea5d2f1c4608232e07d3aa3d998e5135", "c8ffe9a587b126f152ed3d89a146b445",
    "f457c545a9ded88f18ecee47145a72c0", "03afdbd66e7929b125f8597834fa83a4",
    "093f65e080a295f8076b1c5722a46aa2", "03afdbd66e7929b125f8597834fa83a4",
    "698d51a19d8a121ce581499d7b701668", "d82c8d1619ad8176d665453cfb2e55f0",
    "b53b3a3d6ab90ce0268229151c9bde11", "9f61408e3afb633e50cdf1b20de6f466",
    "7f39f8317fbdb1988ef4c628eba02591", "07e1cd7dca89a1678042477183b7ac3f",
    "a1d0c6e83f027327d8461063f4ac58a6", "7f6ffaa6bb0b408017b62254211691b5",
    "d67d8ab4f4c10bf22aa353e27879133c", "9f61408e3afb633e50cdf1b20de6f466",
    "e369853df766fa44e1ed0ff613f563bd", "5fd0b37cd7dbbb00f97ba6ce92bf5add",
    "67c6a1e7ce56d3d6fa748ab6d9af3fd7", "3416a75f4cea9109507cacd8e2f2aefc",
    "b53b3a3d6ab90ce0268229151c9bde11", "1c383cd30b7c298ab50293adfecb7b18",
    "3416a75f4cea9109507cacd8e2f2aefc", "da4fb5c6e93e74d3df8527599fa62642",
    "c8ffe9a587b126f152ed3d89a146b445", "c0c7c76d30bd3dcaefc96f40275bdc0a",
    "735b90b4568125ed6c3f678819b6e058", "14bfa6bb14875e45bba028a21ed38046",
    "fc490ca45c00b1249bbe3554a4fdf6fb", "37693cfc748049e45d87b8c7d8b9aacd",
    "37693cfc748049e45d87b8c7d8b9aacd", "98f13708210194c475687be6106a3b84",
    "3c59dc048e8850243be8079a5c74d079", "fc490ca45c00b1249bbe3554a4fdf6fb",
    "33e75ff09dd601bbe69f351039152189", "4e732ced3463d06de0ca9a15b6153677",
    "33e75ff09dd601bbe69f351039152189", "c16a5320fa475530d9583c34fd356ef5",
    "43ec517d68b6edd3015b3edc9a11367b"
];

// 用于存储还原出的字符
$flag = '';

for ($i = 0; $i < count($md5); $i++) {
    for ($j = 0; $j < 256; $j++) {
        // 计算异或操作后的值
        $xor_result = $j ^ $i;
        // 计算MD5值
        $calculated_md5 = md5($xor_result);
        // 如果计算出的MD5值与给定的MD5值匹配,则找到了正确的字符
        if ($calculated_md5 === $md5[$i]) {
            $flag .= chr($j);
            break;
        }
    }
}

echo "Flag: " . $flag . "\n";

?>
BaseCTF{9614c897-f8c3-4e70-85eb-cdc4313f4364}

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